0.64+x^2-2x=0

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Solution for 0.64+x^2-2x=0 equation:



0.64+x^2-2x=0
a = 1; b = -2; c = +0.64;
Δ = b2-4ac
Δ = -22-4·1·0.64
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{1.44}}{2*1}=\frac{2-\sqrt{1.44}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{1.44}}{2*1}=\frac{2+\sqrt{1.44}}{2} $

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